Freund & Wilson (1997) : Prediction of weight of wood from trees (Table 8.24)

Observation

Dbh

Weight

Dbh*Dbh

Wt*Wt

Dbh*Wt

Predicted

Residual

1

5.7

174

32.49

30276

991.8

288.42

-114.42

2

8.1

745

65.61

555025

6034.5

716.97

28.03

3

8.3

814

68.89

662596

6756.2

752.68

61.32

4

7.0

408

49.00

166464

2856.0

520.55

-112.55

5

6.2

226

38.44

51076

1401.2

377.7

-151.7

6

11.4

1675

129.96

2805625

19095.0

1306.23

368.77

7

11.6

1491

134.56

2223081

17295.6

1341.94

149.06

8

4.5

121

20.25

14641

544.5

74.14

46.86

9

3.5

58

12.25

3364

203.0

-104.42

162.42

10

6.2

278

38.44

77284

1723.6

377.7

-99.7

11

5.7

220

32.49

48400

1254.0

288.42

-68.42

12

6.0

342

36.00

116964

2052.0

341.99

0.01

13

5.6

209

31.36

43681

1170.4

270.56

-61.56

14

4.0

84

16.00

7056

336.0

-15.14

99.14

15

6.7

313

44.89

97969

2097.1

466.98

-153.98

16

4.0

60

16.00

3600

240.0

-15.14

75.14

17

12.1

1692

146.41

2862864

20473.2

1431.22

260.78

18

4.5

74

20.25

5476

333.0

74.14

-0.14

19

8.6

515

73.96

265225

4429.0

806.25

-291.25

20

9.3

766

86.49

586756

7123.8

931.25

-165.25

21

6.5

345

42.25

119025

2242.5

431.27

-86.27

22

5.6

210

31.36

44100

1176.0

270.56

-60.56

23

4.3

100

18.49

10000

430.0

38.43

61.57

24

4.5

122

20.25

14884

549.0

74.14

47.86

25

7.7

539

59.29

290521

4150.3

645.54

-106.54

26

8.8

815

77.44

664225

7172.0

841.96

-26.96

27

5.0

194

25.00

37636

970.0

163.42

30.58

28

5.4

280

29.16

78400

1512.0

234.85

45.15

29

6.0

296

36.00

87616

1776.0

341.99

-45.99

30

7.4

462

54.76

213444

3418.8

591.98

-129.98

31

5.6

200

31.36

40000

1120.0

270.56

-70.56

32

5.5

229

30.25

52441

1259.5

252.7

-23.7

33

4.3

125

18.49

15625

537.5

38.43

86.57

34

4.2

84

17.64

7056

352.8

20.57

63.43

35

3.7

70

13.69

4900

259.0

-68.71

138.71

36

6.1

224

37.21

50176

1366.4

359.84

-135.84

37

3.9

99

15.21

9801

386.1

-33

132

38

5.2

200

27.04

40000

1040.0

199.14

0.86

39

5.6

214

31.36

45796

1198.4

270.56

-56.56

40

7.8

712

60.84

506944

5553.6

663.4

48.6

41

6.1

297

37.21

88209

1811.7

359.84

-62.84

42

6.1

238

37.21

56644

1451.8

359.84

-121.84

43

4.0

89

16.00

7921

356.0

-15.14

104.14

44

4.0

76

16.00

5776

304.0

-15.14

91.14

45

8.0

614

64.00

376996

4912.0

699.11

-85.11

46

5.2

194

27.04

37636

1008.8

199.14

-5.14

47

3.7

66

13.69

4356

244.2

-68.71

134.71

Sum

289.2

17359

1981.98

13537551

142968.3

Sum =

0

Mean

6.15

369.34

42.17

288033

3041.9

SS =

670190.7322

n

47

47

47

47

47

 

 


Intermediate Calculations
            Sum X =          289.2                           Sum Y =          17359 
            Sum X2 =         1981.98                       Sum Y2 =         13537551       
            Mean X=         6.153191489               Mean Y=         369.3404255
            Sum XY =        142968.3                     n =       47       
 
Correction factors and Corrected values (Sums of squares and cross-products)
            CF for X =       Cxx =    1779.502979               Corrected SS X =        Sxx =    202.4770213
            CF for Y =       Cyy =    6411380.447               Corrected SS Y =        Syy =    7126170.553
            CF for XY =    Cxy =    106813.2511               Corrected SS XY =     Sxy =    36155.04894
 
Model Parameter Estimates
            Slope = b1 =     36155.04894 / 202.4770213   =178.5637141
            Intercept = b0 =            369.3404255 - 178.5637141 * 6.153191489 = -729.3963003
            Regression Line            Yi = b0 + b1 * Xi  + ei
                                                Yi = -729.3963003 + 178.5637141 * Xi  + ei 
 
ANOVA Table
            SSTotal =7126170.553
            SSRegression   36155.048942 / 202.4770213 =  6455979.821
            SSError = 7126170.553 - 6455979.821 = 670190.7322
 
            Source              df                           SS                        MS                               F
            Regression          1           6455979.821         6455979.821            433.4871821
            Error                 45          670190.7322         14893.12738
            Total                 46          7126170.553
 

Standard error of b1 :             where t(0.05/2, 45 df) = 2.014103 ;     = 8.576401034

P(178.5637 - 2.0141*8.5764 £ b1 £ 178.5637 + 2.0141*8.5764 ) = 0.95 

<>P( 161.289956 £ b1 £ 195.8375 ) = 0.95

<>

 

Testing b1 against a specified value :  H0: b1 = 200 versus H1: b1 ¹ 200

            = (178.5637141 - 200) / 8.576401034 = -2.49945

            Note that  t2 = F = 6.247251 ;  This test would be done in SAS as an F statement

 

The variance of a linear combination is given by the sum of the variances plus twice the covariances.

            e.g. for            A = aX + bY + cZ

            then                 Var(A) = a2s2X  +  b2s2Y  +  c2s2Z  +  2(absXY  +  acsXZ  +  bcsYZ)

            where the covariances are equal to zero if the variables are independent

For the linear combination , the standard error of   is as follows. 

            Standard error of the regression line ( ):    


The calculation above DOES NOT assume that the covariances of the regression coefficients are independent.  However, for the variance of individual points the linear combination is .  For this linear combination the terms for the predicted value and residuals are assumed independent (i.e.  is independent of ei). 

           

Standard error of b0 is the same as the standard error of the regression line where Xi = 0

            SQRT(14893.12738(0.021276596 + (0 - 37.8617655) / 202.4770213 = 55.69366336

Confidence interval on b0                  where b0 =  -729.3963003  and t(0.05/2, 45 df) = 2.014103

            P(-729.3963 - 2.0141*55.6937 < b0 < -729.3963 + 2.0141*55.6937)=0.95

            P( -841.5690916 < b0 < -617.223509 ) = 0.95

Estimate and standard error of an individual observation (e.g. the weight of wood for a ten-inch-diameter tree)

            Y =-729.3963003 + 178.5637141* X = -729.3963003 + 178.5637141 * 10 =1056.240841

            se(bx=10) =14893.1274*(1 + 0.02128 + (10 - 14.79794) / 202.4770) = 127.6654

            P(1056.2408-2.0141*127.6654 <  µx=10 < 1056.2408+2.0141*127.6654)=0.95

            P( 799.1094964   <  µx=10 <   1313.372185 ) = 0.95

 

Calculate the coefficient of Determination and correlation

            R2 =     0.905953594               or  90.59535936 %

            r =        0.951815945  




Modified: August 16, 2004
James P. Geaghan